Remember that the equation for the area of a rectangle is A = LW, where A=are of the rectangle, L=length of the rectangle and W=width of the rectangle.
You're given that L = 12yds and W = [tex] \frac{31}{5} [/tex] yds. Plug these values into your equation for the area of a rectangle and solve for A:
[tex]A = LW\\
A = (12\:yds)(\frac{31}{5}\:yds)\\
A = \frac{12 \times 31}{5} \: yds^{2} \\
A = 74.4 \: yds^{2} [/tex]
The area of the rectangle is 74.4 [tex]yds^{2}[/tex].
