kx-3y=4 4x-5y=7 In the system of equations above, k is a constant and x and y are variables. For what value of k with a symptom of equation have no solution?
To solve this problem, you need to recognize that the ratios of the coefficients must be equal. So the ratio for this system would be k/4 = -3/-5. Solving for k we get k = (3)*(4)/5 = 12/5, hence the answer is A. Hope that helps!
