Jan'ai was asked to determine the minimum for a function with zeros located at -1 and 5, which also has a y-intercept of (0,25). Her work is shown.

Begin to write a function in factored form. f(x) = a(x+1)(x-5)
Substitute to determine a. -25 = a(0+1)(0-5)
Simplify and solve to find a. a=5
Rewrite the function. f(x) = 5(x+1)(x-5)
Rewrite in standard form. f(x) = 5x^2-20x-25
Find the x-coordinate of the vertex. x = -20/2(5) = -20/10; x = -2
Find the y-coordinate of the vertex. y = 5x^2-20x-25
y = 5(-2)^2-20(-2)-25
y = 35 so (-2,35)

Which best describes the first error in Jan'ai's work?

A) She incorrectly determined the factors for the beginning function.
B) She incorrectly determined the a value.
C) She incorrectly transformed the equation to standard form.
D) She incorrectly determined the x-coordinate of the vertex.

Respuesta :

Answer:

!!! The answer is D !!!

Step-by-step explanation:

just got it right

From the calculation above, we can see that She incorrectly determined the a value.

Determining the function with given intercepts

The standard factored form of the polynomial function is given as:

f(x) = a(x - a)(x - b)

where

a and b are the x-intercept

If the zeros are located at -1 and 5, then the resulting function will be:

f(x) = a(x-(-1))(x-5)

f(x) = a(x+1)(x-5)

If the y-intercept is. (0, 25), hence

25 = a(0+1)(0-5)

25 = -5a
a = -5

Substitute to have;

f(x) = -5(x+1)(x-5)

From the calculation above, we can see that She incorrectly determined the a value.

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