An architect planned to construct two similar stone pyramid structures in a park. The figure below shows the front view of the pyramids in her plan, but there is an error in the dimensions:

Two similar scalene triangles PQR and ABC with angle P congruent to angle A, angle Q congruent to angle B, and QR and BC as the bases of the triangles. The length of PQ is 6 feet, the length of QR is 9.5 feet, and the length of RP is 7.5 feet. The length of AB is 4 feet, the length of BC is 7 feet, and the length of CA is 5 feet.

Which of the following changes should she make to the length of side RQ to correct her error?

Change the length of side RQ to 9 feet
Change the length of side RQ to 10.5 feet
Change the length of side RQ to 8 feet
Change the length of side RQ to 11.5 feet

An architect planned to construct two similar stone pyramid structures in a park The figure below shows the front view of the pyramids in her plan but there is class=

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Answer:

The correct option is 2. She can change the length of side RQ to 10.5 feet to correct her error.

Step-by-step explanation:

In triangle PQR and ABC,

[tex]\angle P=\angle A[/tex]                       (Given)

[tex]\angle Q=\angle B[/tex]                       (Given)

By AA rule of similarity,

[tex]\triangle PQR=\triangle ABC[/tex]

The corresponding sides of similar triangles are proportional.

[tex]\frac{PQ}{AB}=\frac{RQ}{CB}=\frac{PR}{AC}[/tex]

[tex]\frac{PQ}{AB}=\frac{6}{4}=1.5[/tex]

[tex]\frac{RQ}{CB}=\frac{9.5}{7}=1.35714285714[/tex]

[tex]\frac{PQ}{AB}neq \frac{RQ}{CB}[/tex]

It means there is an error in the dimensions. Let the new length of RQ be x.

[tex]\frac{PQ}{AB}=\frac{RQ}{CB}[/tex]

[tex]\frac{6}{4}=\frac{x}{7}[/tex]

Multiply both sides by 7.

[tex]\frac{6\times 7}{4}=x[/tex]

[tex]\frac{42}{4}=x[/tex]

[tex]10.50=x[/tex]

Therefore the length of RQ must be 10.50. The correct option is 2.