The current intensity is defined as the amount of charge that passes through a certain point in a certain time interval:
[tex]I= \frac{Q}{\Delta t} [/tex]
where
I is the current
Q the charge
[tex]\Delta t[/tex] is the time interval.
For the wire in our problem, the current is [tex]I=6 mA=0.006 A[/tex] while the charge is [tex]Q=3.00 C[/tex], so we can find the time interval by re-arranging the previous formula and using these data:
[tex]\Delta t = \frac{Q}{I} = \frac{3.00 C}{0.006 A}=500 s [/tex]
so, the charge takes 500 s to pass through a certain point of the wire.
