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PLEASE HELP
Use the distance formula d=(x2−x1)2+(y2−y1)2−−−−−−−−−−−−−−−−−−√

to find the length of the line with endpoints at (1,3) and (3,1)?


Question 2 options:


8√



8


32−−√



32
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Question 3 (1 point)
Question 3 Saved

What is the slope of the line that is perpendicular to a line whose equeation is 3y = -4x + 2 ?
Question 3 options:


34



-34



43



-43

Respuesta :

mathstudent55
2.

[tex] d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} [/tex]

[tex] d = \sqrt{(3 - 1)^2 + (1 - 3)^2} [/tex]

[tex] d = \sqrt{(2)^2 + (2)^2} [/tex]

[tex] d = \sqrt{4 + 4} [/tex]

[tex] d = \sqrt{8} [/tex]

3.

[tex] 3y = -4x + 2 [/tex]

[tex] y = - \dfrac{4}{3} x + \dfrac{2}{3} [/tex]

Slope of line of given equation is -4/3.

Slope of perpendicular is -3/4.

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