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09-04-2018
Mathematics

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If the endpoints of the diameter of a circle are (6,3) and (2,1), what is the standard form of the circle?

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popalabdulqayou popalabdulqayou

20-04-2018

[tex]r= \sqrt{5} [/tex][tex] \frac{8}{2} , \frac{4}{2} [/tex][tex]distance= \sqrt{(x-x)^2+(y-y)^2} = \sqrt{(2-6)^2+(1-3)^2} = 2\sqrt{5} [/tex][tex]r= \sqrt{5} [/tex]
through midpoint we find and b to be (4,2).
[tex](x-4)^2+(y-2)^2=5[/tex]

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