Respuesta :

transitionstate
Molar Mass of Fe₂O₃  =  159.69 g/mol

As we know,
                                            Moles  =  Mass / M.mass
Solving for Mass,
                                            Mass  =  Moles ×  M.mass
Putting Values,
                                            Mass  =  0.50 mol ×159.69 g/mol

                                            Mass  =  79.84 g
LucianoBordoli

Answer:

79.844 g.

Explanation:

First we are going to calculate the molar mass of [tex]Fe_{2}O_{3}[/tex]

The molar mass of Fe is [tex]55.845\frac{g}{mol}[/tex] this means that 1 mol of Fe has a mass of 55.845 g.

The molar mass of O is [tex]15.999\frac{g}{mol}[/tex] this means that 1 mol of O has a mass of 15.999 g

To calculate the molar mass of [tex]Fe_{2}O_{3}[/tex] we calculate the following number :

[tex]2.(55.845\frac{g}{mol})+3.(15.999\frac{g}{mol})=159.687\frac{g}{mol}[/tex]

This means that 1 mol of [tex]Fe_{2}O_{3}[/tex] has a mass of 159.687 g.

Finally, in 0.500 mol of [tex]Fe_{2}O_{3}[/tex] we have

[tex]159.687\frac{g}{mol}.(0.500mol)=79.844g[/tex]

There are 79.844 g of [tex]Fe_{2}O_{3}[/tex] in 0.500 mol of [tex]Fe_{2}O_{3}[/tex]