Answer:- There are 131 g of [tex]Fe_2O_3[/tex] in 0.82 moles of it.
Solution:- It is a mol to gram conversion. We have been given with 0.82 moles of [tex]Fe_2O_3[/tex] and asked to convert it to grams.
For mol to gram conversion we multiply the moles by the molar mass.
Atomic mass of Fe is 55.85 and atomic mass of O is 16. So, molar mass of [tex]Fe_2O_3[/tex] = 2(55.85) + 3(16)
= 111.7 + 48
= [tex]159.7(\frac{g}{mol})[/tex]
Let's convert the moles to grams as:
[tex]0.82mol(\frac{159.7g}{mol})[/tex]
= 131 g
So, there are 131 g of [tex]Fe_2O_3[/tex] present in 0.82 mol of it.
