True mean = mean +/-[tex] \frac{sd}{ \sqrt{n} } [/tex]
Where,
sd = standard deviation = 0.15 oz
mean = 36 oz
n= sample size = 40
Then,
True mean = 36+/- [tex] \frac{0.15}{ \sqrt{40} } [/tex] = 36+/-0.024 oz
Therefore, sample has a mean of between 35.976 oz and 36.024 oz