Answer : The volume of 0.10 M NaOH prepared can be 750 mL.
Explanation :
Formula used :
[tex]M_1V_1=M_2V_2[/tex]
where,
[tex]M_1\text{ and }V_1[/tex] are the initial molarity and volume of NaOH.
[tex]M_2\text{ and }V_2[/tex] are the final molarity and volume of NaOH.
We are given:
[tex]M_1=0.30M\\V_1=250mL\\M_2=0.10M\\V_2=?[/tex]
Putting values in above equation, we get:
[tex]0.30M\times 250mL=0.10M\times V_2\\\\V_2=750mL[/tex]
Hence, the volume of 0.10 M NaOH prepared can be 750 mL.
