For a particular reaction, δh = 120.5 kj and δs = 758.2 j/k. calculate δg for this reaction at 298 k.

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straightbarz3513 straightbarz3513

09-04-2018
Chemistry

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For a particular reaction, δh = 120.5 kj and δs = 758.2 j/k. calculate δg for this reaction at 298 k.

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transitionstate transitionstate · Answer 1 · 2018-04-18T19:07:50+02:00

Data Given:
Change in Entropy =  ΔH = 120.5 kJ = 1.20 × 10⁵ J

Temperature = T = 298 K

Change in Entropy =  ΔS = 758.2 J/K

Using Formula,
  ΔG =  ΔH - T ΔS
Putting Values,
  ΔG = (1.20 × 10⁵ J) - (298 K × 758.2 J/K)

  ΔG = -1.059 × 10⁵ J

  ΔG = -105.94 kJ