Respuesta :

The reaction will take place according to the equation;
P4 + 10Cl2 = 4PCl5
1 mole of Cl2 contains 70.9 g/mol
Therefore, the number of moles of Cl2 will be;
  = 57 g/ 70.9 g/mol
  = 0.804 moles
The mole ratio of Cl2 : PCl5 = 10:4
Therefore; the number of moles of PCl5 = (0.804/10)×4 
       = 0.3216 moles

Answer : The number of moles of [tex]PCl_5[/tex] produced can be 0.321 moles.

Solution : Given,

Mass of [tex]Cl_2[/tex] = 57.0 g

Molar mass of [tex]Cl_2[/tex] = 71 g/mole

First we have to calculate the moles of [tex]Cl_2[/tex].

[tex]\text{ Moles of }Cl_2=\frac{\text{ Mass of }Cl_2}{\text{ Molar mass of }Cl_2}=\frac{57.0g}{71g/mole}=0.803moles[/tex]

Now we have to calculate the moles of [tex]PCl_5[/tex]

The balanced chemical reaction is,

[tex]P_4+10Cl_2\rightarrow 4PCl_5[/tex]

From the reaction, we conclude that

As, 10 mole of [tex]Cl_2[/tex] react to give 4 mole of [tex]PCl_5[/tex]

So, 0.803 moles of [tex]Cl_2[/tex] react to give [tex]\frac{0.803}{10}\times 4=0.321[/tex] moles of [tex]PCl_5[/tex]

Therefore, the number of moles of [tex]PCl_5[/tex] produced can be 0.321 moles.