Respuesta :
Answer:
a) increase, ΔS is positive
b) ΔS = 0.089 kJ/K
Explanation:
a) Entropy is a thermodynamic quantity which measures the degree of randomness of a system. Greater the disorder, greater will be the entropy. For different states of matter the entropy increases from solid to liquid to gas.
In the given example, when Br2(l) boils it changes into the gas phase
Br2(l) ↔ Br2(g)
Thus, entropy will increase. i.e. S(product) > S(reactant) and ΔS is positive.
b) It is given that:
Br2(l) ↔ Br2(g) ΔH = 29.6 kJ/mol
[tex]dS = \frac{qrev}{T} \\\\qrev = dH * moles = 29.6 kJ/mol * 1 mol = 29.6 kJ\\\\dS = \frac{29.6}{58.8 + 273} K = 0.089 kJ/K[/tex]
Answer: (a) increase [tex]\delta S[/tex] is positive
(b) Value of [tex]\delta S[/tex] is 89.21 J/molK
Explanation:
Boiling point is defined as the temperature where atmospheric pressure becomes equal to the vapor pressure of a liquid.
Entropy is the degree of randomness present within the molecules of a substance.
Further Explanation:
At constant temperature and pressure, the amount of heat energy necessary to change one mole of a substance into gaseous phase from liquid phase is known as molar enthalpy of vaporization.
As due to heating of a liquid there occurs an increase in entropy due to increase in randomness between the molecules. Therefore, entropy will increase.
As the reaction is [tex]Br_{2}(l) \rightarrow Br_{2}(g)[/tex]
The given data is as follows.
T = [tex]58.8^{o}C[/tex]
= (58.8 + 273) K
= 331.8 K
[tex]\Delta H_{vap}[/tex] = 29.6 kJ/mol
As 1 kJ = 1000 J.
So, 29.6 kJ/mol = 29600 J/mol.
Relation between change in entropy and change in enthaly are as follows:
[tex]\Delta S_{vap}[/tex] = [tex]\frac{\Delta H}{T}[/tex]
Now, putting the given values into the above formula as follows:
[tex]\Delta S_{vap}[/tex] = [tex]\frac{\Delta H}{T}[/tex]
= [tex]\frac{29600 J/mol}{331.8 K}[/tex]
= 89.21 J/mol K
Since, liquid molecules are changing into gas molecules therefore, there will occur an increase in entropy.
Learn more
https://brainly.com/question/13147785
https://brainly.com/question/9959863
Keywords:
enthalpy of vaporization, change in entropy.
