Respuesta :

kenmyna
NH4I (aq)  +  KOH  (aq)  in   chemical   equation  gives

   NH4I (aq)  +  KOH (aq)   =  KI  (aq)  +  H2O(l)  +  NH3  (l)

Ki  is  in  aqueous  state  H2o   is  in   liquid  state  while  NH3  is  in  liquid  state

from  the  equation  above  1 mole of  NH4I (aq) react  with  1 mole of KOH(aq) to  form  1mole of KI(aq) ,  1mole of H2O(l)  and 1  Mole  of NH3(l)
pstnonsonjoku

Answer:

NH4I(aq) + KOH(aq) -------->KI(aq) + NH3(g) + H2O(l)

Explanation:

NH4I(aq) + KOH(aq) -------->KI(aq) + NH3(g) + H2O(l)

This is a reaction of aqueous ammonium iodide and aqueous potassium hydroxide to yield aqueous potassium iodide, gaseous ammonia and liquid water as shown above.