Respuesta :

The atomic mass of sulfur is 32.07 g/mole. 
From the Avagadro constant  1 mole of a substance contains 6.022 × 10^23 particles;
1 mole of sulfur contains 6.022 ×10^23 atoms
But 1 mole is equal to 32.07 g
Therefore; 
      6.022 ×10^23 atoms = 32.07
Thus; 2.23 × 10^23 atoms = ?
       = (2.23 ×10^23 ×32.07)/ 6.022×10^23
       = 11.876 g
Eduard22sly

The mass of 2.23×10²³ atoms of sulphur is 11.85 g

From a detailed understanding of the Avogadro's hypothesis, we understood that 1 mole of any substance contains 6.02×10²³ atoms.

The above statement implies that:

6.02×10²³ atoms = 1 mole of sulphur

Recall:

1 mole of sulphur = 32 g

Thus, we can say that:

6.02×10²³ atoms = 32 g of sulphur

With the above information, we can obtain the mass of 2.23×10²³ atoms of sulphur. This can be obtained as follow:

6.02×10²³ atoms = 32 g of sulphur

Therefore,

2.23×10²³ atoms = [tex]\frac{32 * 2.23*10^{23} }{6.02*10^{23} }\\\\[/tex]

2.23×10²³ atoms = 11.85 g of sulphur

Thus, the mass of 2.23×10²³ atoms of sulphur is 11.85 g

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