Respuesta :
Balance chemical equation is as follow,
P₄ + 10 Cl₂ → 4 PCl₅
First find moles for given masses of P₄ and Cl₂.
For P₄:
Moles = Mass / M.mass
Moles = 26 g / 123.88 g/mol
Moles = 0.209 moles
For Cl₂:
Moles = 50 g / 70.9 g/mol
Moles = 0.70 moles
According to balance equation,
For 1 mole of P₄ = 10 moles of Cl₂ is required
So,
For 0.209 moles of P₄ = X moles of Cl₂ is reuired
Solving for X,
X = (0.209 mol × 10 mol) ÷ 1 mol
X = 2.09 mol of Cl₂
But we are provided only with 0.70 moles of Cl₂, means Cl₂ is a limiting reactant, and controls the yield of PCl₅, So,
When,
709 g of Cl₂ produced = 832.88 g of PCl₅
Then,
50 g of Cl₂ will produce = X g of PCl₅
Solving for X,
X = (50 g × 832.88 g) ÷ 709 g
X = 58.73 g of PCl₅
P₄ + 10 Cl₂ → 4 PCl₅
First find moles for given masses of P₄ and Cl₂.
For P₄:
Moles = Mass / M.mass
Moles = 26 g / 123.88 g/mol
Moles = 0.209 moles
For Cl₂:
Moles = 50 g / 70.9 g/mol
Moles = 0.70 moles
According to balance equation,
For 1 mole of P₄ = 10 moles of Cl₂ is required
So,
For 0.209 moles of P₄ = X moles of Cl₂ is reuired
Solving for X,
X = (0.209 mol × 10 mol) ÷ 1 mol
X = 2.09 mol of Cl₂
But we are provided only with 0.70 moles of Cl₂, means Cl₂ is a limiting reactant, and controls the yield of PCl₅, So,
When,
709 g of Cl₂ produced = 832.88 g of PCl₅
Then,
50 g of Cl₂ will produce = X g of PCl₅
Solving for X,
X = (50 g × 832.88 g) ÷ 709 g
X = 58.73 g of PCl₅
PCl₅ mass = 58.73 g
Further explanation
The reaction equation is the chemical formula of reactants and products
A reaction coefficient is a number in the chemical formula of a substance involved in the reaction equation. The reaction coefficient is useful for equalizing reactants and products
Reaction
P₄ + 10 Cl₂ → 4 PCl₅
We look for moles of each reactant so we can determine the limiting of the reactants
- mole P₄
mass 26.0 g
molar mass: 123.9
mole = mass : molar mass
mole = 26 : 123.9
mole: 0.2114
- mole Cl₂
mass 50 g
molar mass: 71
mole = mass : molar mass
mole = 50 : 71
mole: 0.7042
From the coefficient of the equation above, it shows that the ratio of mol P₄: mol Cl₂ = 1:10
A method that can be used to find limiting reactants is to divide the number of moles of known substances by their respective coefficients, and small or exhausted reactans become a limiting reactants
ratio P₄: 0.2114: 1 = 0.2114
ratio Cl₂: 0.7042: 10 = 0.07042
Because Cl₂ ratio smaller then Cl₂ becomes the limiting reactants
So mole PCl₅ is based on mole Cl₂
From the coefficient of reaction: mol PCl₅: mol Cl₂ = 4: 10
then mole PCl₅ = 4/10 x 0.7042 = 0.28168
molar mass PCl₅= 208.5
mass PCl₅ = mole x molar mass
PCl₅ mass = 0.28168 x 208.5
PCl₅ mass = 58.73 g
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