Respuesta :
Kinetic energy is given by 1/2 MV²
k.e = 1/2 mv²
1.9 × 10^3 = 1/2m(v/2)²
1.9 ×10^3 = 1/8 mv²
1.9 × 10^3 = 1/4(1/2mv²)
= (1.9 × 10^3)/ 4
= 4.75 × 10^2 joules
The new kinetic energy will therefore be 4.7 × 10^2 joules.
k.e = 1/2 mv²
1.9 × 10^3 = 1/2m(v/2)²
1.9 ×10^3 = 1/8 mv²
1.9 × 10^3 = 1/4(1/2mv²)
= (1.9 × 10^3)/ 4
= 4.75 × 10^2 joules
The new kinetic energy will therefore be 4.7 × 10^2 joules.
Answer:
B). [tex]KE_f = 4.7 \times 10^2 J[/tex]
Explanation:
As we know that the kinetic energy of the car depends on mass of car and its speed
so we will say that
[tex]KE = \frac{1}{2}mv^2[/tex]
now we know that if we will change the mass or speed of the car then the kinetic energy of the car will change accordingly
so here if we change the velocity of car and decrease it by half
then we have
[tex]KE_f = \frac{1}{2}m(\frac{v}{2})^2[/tex]
so it is given as
[tex]KE_f = \frac{1}{4} KE[/tex]
[tex]KE_f = \frac{1}{4}(1.9 \times 10^3)[/tex]
[tex]KE_f = 4.7 \times 10^2 J[/tex]
