A pyramid with an equilateral-triangle base has a volume of 483√3 cm 3 and a height of 16 cm. What is the length of each side of the equilateral triangle?
V= 1/3 Area of base times Height so, 483 (3)^1/2 =1/3 A (16 cm) 1/3(1/2b^2)16cm = 483(3)^1/2 solve for b to get the sides and it is = 17.7 or 18 approximate.
