Respuesta :

18 c

the answer is 7.5 square units
[tex]((1 + 4) \times 3) \div 2 = (5 \times 3) \div 2 \\ = 15 \div 2 = 7.5[/tex]


18 b

the answer is 10.5 square units
[tex]((5 + 2) \times 3) \div 2 = (7 \times 3) \div 2 \\ = 21 \div 2 = 10.5[/tex]

18 a

the answer is 12 square units
[tex]((4 + 2) \times 4) \div 2 = (6 \times 4) \div 2 \\ = 24 \div 2 = 12[/tex]




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We know the area formula of a trapezium/trapezoid
Area = [tex] \frac{1}{2} (height)[/tex] (side 1 + side 2 )

In these examples, you need to note one thing very carefully, the graph is spaced with 2 units in the axes of x and y. It is not spaced with 1 unit 
Which means:  The axes begin as 2 , 4 , 6 ; - 2 , - 4 , - 6

18 ) c )
    ↓
Base 1 = 2 units
Base 2 = 4 + 4 = 8 units ( Only half the base length was shown, since it is the same below the x-axis, we multiply by 2 )
Height = 6 units

Apply the formula
Area = [tex] \frac{1}{2} [/tex] x 6 x ( 8 + 2 )
         = [tex] \frac{1}{2} [/tex] x 6 x 10
         = 30 units²

18 ) b )
    ↓
Base 1 = 2 + 2 = 4 units
Base 2 = 6 + 4 = 10 units 
Height = 4 + 2 = 6 units

Area = [tex] \frac{1}{2} [/tex] x 6 x ( 10 + 4 )
         = [tex] \frac{1}{2} [/tex] x 6 x 14
         = 42 units²

18 ) a )
    ↓
Base 1 = 2 + 2 = 4 units
Base 2 = 4 + 4 = 8 units
Height = 4 + 4 = 8 units

Area = [tex] \frac{1}{2} [/tex] x 8 x ( 8 + 4 )
         = [tex] \frac{1}{2} [/tex] x 8 x 12
         = 48 units²
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