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A given line has the equation 10x + 2y = −2. What is the equation, in slope-intercept form, of the line that is parallel to the given line and passes through the point (0, 12)? y = ( )x + 12

Respuesta :

10x + 2y = -22y = -10x - 2y = -5x - 1.....slope is -5 and a parallel line will have the same slope(0,12)...x = 0 and y = 12now we sub12 = -5(0) + b12 = b
so your parallel line is : y = -5x + 12 ;) :)
The answer is y=-5x+12 

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