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Isabella has twice as much money invested at 4% as she has invested at 3%, and she has $500 more invested at 5% than she has at 3%. If the annual income from these three investments is $2025, how much does she have invested at 4%

Respuesta :

invested at 3% = x
invested at 4% = 2x
invested at 5% = x+500

0.03x + 0.04(2x) + 0.05(x+500) = 2025
0.03x + 0.08x +0.05x +25 = 2025
0.16x = 2000
x= 12,500
4% = 2x = 12,500 * 2 = $25,000

The total amount invested by Isabella which she has invested at 4%, when the annual income from these three investments is $2025, is $25000.

What is percentage ?

Percentage of a number is the part of the number expressed in the in every hundred. Percentage of a number is expressed with the symbol '%' known as percentage symbol.

Let suppose the Isabella invested x dollars at 3%. Now, Isabella has twice as much money invested at 4% as she has invested at 3%. Thus,

[tex]\rm Invested \;at \;4\%=2x[/tex]

She has $500 more invested at 5% than she has at 3%. Thus,

[tex]\rm Invested \;at \;5\%=x+500[/tex]

The annual income from these three investments is $2025. Thus, the sum of all the three investement amount should be equal to $2025.

[tex]\dfrac{3}{100}(x)+\dfrac{4}{100}(2x)+\dfrac{5}{100}(x+500)=2025\\0.03x+0.08x+0.05x+25=20250.16x=2025-25\\x=\dfrac{2000}{0.16}\\x=25000[/tex]  

Thus, he total amount invested by Isabella which she has invested at 4%, when the annual income from these three investments is $2025, is $25000.

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