a tree casts a shadow 32 feet long .the Angle of elevation of the sun is 62° what is the height of the tree

Respuesta :

[tex] \tan \theta = \dfrac{opp}{adj} [/tex]

[tex] \tan 62^\circ = \dfrac{y}{32~ft} [/tex]

[tex] y = 32 \tan 62^\circ ~ft [/tex]

[tex] y = 60.2 ~ft [/tex]

Answer: The tree is 60.2 ft tall.
90-62= 28
law of sines 28/32= sin 62/h
h= 32 sin 62/sin 28
h= 60.18 feet