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If a sample of oxygen occupies a volume of 2.15 L at a pressure of 58.0 Kpa and a temperature of 25°C what volume of the sample a company at 101.3 K PA and 0°C

Respuesta :

kenmyna
The    volume  of  the sample    a company  at  101.3  KPa   and  o  degrees is  calculated   as  follows

by  use  combined  gas  law

that  is  P1V1/T1=  P2V2/T2

V2 =  P1V1T2/T1P2

T1=  25  +273  =  298  K
P1=  58  kpa
V1=  2.15 L
P2= 101.3  kpa
T2 =  o+273 =  273k
v2=?

V2=  (58  x2.15  x273)/(298 x101.3)   =  1.13  L


dsdrajlin

Answer:

1.13 L

Explanation:

Given data

  • Initial pressure (P₁): 58.0 kPa
  • Initial volume (V₁): 2.15 L
  • Initial temperature (T₁): 25°C + 273.15 = 298 K
  • Final pressure (P₂): 101.3 kPa
  • Final volume (V₂): ?
  • Final temperature (T₂): 0°C + 273.15 = 273 K

We can find the final volume of the oxygen gas using the combined gas law.

[tex]\frac{P_{1}\times V_{1}}{T_{1}} =\frac{P_{2}\times V_{2}}{T_{2}}\\\frac{58.0kPa\times 2.15L}{298K} =\frac{101.3kPa\times V_{2}}{273K}\\V_{2}=1.13L[/tex]

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