This seems like a right angle triangle situation the height is 3ft the base is 4ft so we're looking for the hypothenus so we can use the Pythagoras Theorem which is the square of the hypothenus is equal to the sum of the square of the two other sides hyp^2 is equal to opp^2+ adj^2 hyp^2 equals to 3^2 + 4^2 9+16 25 hyp^2 equals to 25 [tex] \sqrt{25} [/tex] equals to 5 the ramp has to be 5ft long
