Respuesta :
You mean "completing the square," don't you? ;)
(x+7)(x-9)=25 can be expanded: x^2 - 9x + 7x - 63 + 25, which becomes
x^2 -2x = 38.
Let's now complete the square:
x^2 - 2x + (1)^2 - (1)^2 = 38, or x^2 - 2x + 1 = 39
Rewrite that as (x-1)^2 = 39
Take the sqrt of both sides: x-1 = plus or minus sqrt(39)
Write the roots: x = 1+sqrt(39) and x = 1 = sqrt(39) (answers)
(x+7)(x-9)=25 can be expanded: x^2 - 9x + 7x - 63 + 25, which becomes
x^2 -2x = 38.
Let's now complete the square:
x^2 - 2x + (1)^2 - (1)^2 = 38, or x^2 - 2x + 1 = 39
Rewrite that as (x-1)^2 = 39
Take the sqrt of both sides: x-1 = plus or minus sqrt(39)
Write the roots: x = 1+sqrt(39) and x = 1 = sqrt(39) (answers)
Answer with Step-by-step explanation:
we are given a equation:
(x+7)(x-9)=25
⇒ x(x-9)+7(x-9)=25
⇒ x²-9x+7x-63=25
⇒ x²-2x=25+63
⇒ x²-2x=88
adding 1 on both sides
⇒ x²-2x+1=88+1
⇒ (x-1)²=89
⇒ [tex]x-1=\sqrt{89}\ or\ x-1=-\sqrt{89}[/tex]
⇒ [tex]x=\sqrt{89}+1\ or\ x=-\sqrt{89}+1[/tex]
Hence, value of x are:
[tex]x=\sqrt{89}+1\ or\ x=-\sqrt{89}+1[/tex]