What is the area of Figure ABCD?

A trapezoid ABCD is drawn with length of parallel sides AB and CD equal to 10 inches and 12 inches, respectively. The length of one of the non-parallel sides BC is 6 inches. Side BC is perpendicular to DC. A perpendicular line drawn from A to side CD meets CD at E.
pick from one of the 4 awnsers plz

54 square inches

60 square inches

66 square inches

72 square inches

What is the area of Figure ABCD A trapezoid ABCD is drawn with length of parallel sides AB and CD equal to 10 inches and 12 inches respectively The length of on class=

Respuesta :


[tex](6 \times 10) + \frac{1}{2}(6 \times 2) = 66 [/tex]

Answer:

The area of the given trapezoid in a figure ABCD is 66 square inches

Step-by-step explanation:

We have given that the, a trapezoid ABCD is drawn with a length of parallel sides AB and CD equal to 10 inches and 12 inches, respectively.

The length of one of the non-parallel sides of BC is 6 inches.

Side BC is perpendicular to DC.

A perpendicular line drawn from A to side CD meets CD at E.

What is the area of the trapezoid?

The area of a trapezoid is the number of unit squares that can be fit into it and it is measured in square units.

We have the area of the rectangle is given by,

Area of the rectangle= 10 x 6

Area of the rectangle= 60

Then, the area of the triangle is,

Therefore the area of the trapezoid is,

Area of the triangle+ area of rectangle= Area of the trapezoid

Area of the trapezoid= 60 + 6

Area of the trapezoid = 66 inches