Answer:
Step-by-step explanation:
Given that the difference of sample means of two populations is 108.7, and the standard deviation of the difference in sample means is 32.
H0: difference inmeans =0
Ha: difference inmeans not equal to 0
(Two tailed test)
Test statistic = mean difference/std deviation
[tex]=\frac{108.7}{32}\\=3.40[/tex]
For 68% confidence level, }z}<1
Here z =3.40 >1
Hence reject null hypothesis
The difference between the means cannot be 0 and there is statistical evidence at 68% level to reject null hypothesis
