Respuesta :
One rectangle that has a length of 8, and width of 2. The area would be 16 and the perimeter would be 20.
The other rectangle has a length of 6, and width of 4. Area is 24 and perimeter is 20.
The other rectangle has a length of 6, and width of 4. Area is 24 and perimeter is 20.
Hello!
Here are two possible rectangles with a perimeter of 20 units and their areas:
_____________________________
RECTANGLE #1:
The dimensions could be 2 and 8.
P = 2l + 2w
P = 2(2) + 2(8)
P = 20 units
A = l × w
A = 2 × 8
A = 16 units^2
The area would be 16 units^2.
_____________________________
RECTANGLE #2:
The dimensions could be 6 and 4.
P = 2l + 2w
P = 2(6) + 2(4)
P = 20 units
A = l × w
A = 6 × 4
A = 24 units^2
The area of the rectangle is 24 units^2.
Here are two possible rectangles with a perimeter of 20 units and their areas:
_____________________________
RECTANGLE #1:
The dimensions could be 2 and 8.
P = 2l + 2w
P = 2(2) + 2(8)
P = 20 units
A = l × w
A = 2 × 8
A = 16 units^2
The area would be 16 units^2.
_____________________________
RECTANGLE #2:
The dimensions could be 6 and 4.
P = 2l + 2w
P = 2(6) + 2(4)
P = 20 units
A = l × w
A = 6 × 4
A = 24 units^2
The area of the rectangle is 24 units^2.