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A scientist uses a submarine to study ocean life. She begins at sea level, which is at an elevation of 0 feet She travels straight down for 90 seconds at a speed of 3.5 feet per second. She then travels directly up for 30 seconds at a speed of 2.2 feet per second. After this 120-second period, how much time, in seconds, will it take for the scientist to travel back to sea level at the submarine’s maximum speed of 4.8 feet per second? Round your answer to the nearest tenth of a second.

Respuesta :

CyCandy
Distance = speed*time
 1st              = 90*3.5
               = 315ft
2nd         = 30*2.2
               = 66ft
0-315+66= -315+66= -249ft
(249/4.8)= 51.875 = 51.86 seconds
Hope this helps.
fichoh

Using the speed - distance relationship, the time taken for the scientist to travel back to sea level would be 51.9 seconds

Recall :

  • Distance = Speed × time

First travel :

Distance covered = 90 × 3.5 = 315 feets

Second travel :

Distance covered = 30 × 2.2 = 66 feets

Net change in position from sea level :

(315 - 66) feets = 249 feets

Maximum speed = 4.8 feets per second

Time taken = Distance / speed

Time taken = 249 ÷ 4.8 = 51.875 seconds

Hence, it will take 51.9 seconds to return to sea level.

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