Balance Equation is as followm
F₂ + CaBr₂ → CaF₂ + Br₂
According to equation 1 mole of F₂ reacts with 1 mole of CaBr₂. So,
As,
199.89 g CaBr₂ reacts with = 1 mole of F₂
Then,
2.67 g of CaBr₂ will react with = X mole of F₂
Solving for X,
X = (2.67 g × 1 mole) ÷ 199.89 g
X = 0.0133 moles of F₂
Now, Covert moles of F₂ into Volume, Assuming it as Ideal gas,
So, Acc. to Ideal Gas Equation
P V = n R T
Solving for V,
V = n R T / P
Putting Values,
V = (0.0133 mol × 0.0820 atm.L.mol⁻¹.K⁻¹ × 313 K) ÷ 4.31 atm
V = 0.0792 L
Converting into mL,
= 0.0792 × 1000
= 79.2 mL
