Respuesta :
Strontium Hydroxide Ionizes as follow,
Sr(OH)₂ → Sr²⁺ + 2 OH⁻
So,
1 mole of Sr(OH)₂ produces 2 moles of Hydroxides,
If the concentration of 1 M Sr(OH)₂ produces 2 M OH⁻ ions then, 0.082 M Sr(OH)₂ will produce,
[OH⁻] = 2 × 0.082
[OH⁻] = 0.164 M
Sr(OH)₂ → Sr²⁺ + 2 OH⁻
So,
1 mole of Sr(OH)₂ produces 2 moles of Hydroxides,
If the concentration of 1 M Sr(OH)₂ produces 2 M OH⁻ ions then, 0.082 M Sr(OH)₂ will produce,
[OH⁻] = 2 × 0.082
[OH⁻] = 0.164 M
The value of [OH⁻] = 0.164 M.
What is a solution?
A solution is a mixture of the solute to the solvent.
The ionization of strontium hydroxide is
Sr(OH)₂ → Sr²⁺ + 2 OH⁻
It is clear that 1 mol of Sr(OH)₂ is producing 2 moles of hydroxide.
Then for 0.082 M Sr(OH)₂ will produce
[OH⁻] = 2 × 0.082
[OH⁻] = 0.164 M
Thus, the [OH⁻] = 0.164 M.
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