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The graph of the function f(x) = –(x + 6)(x + 2) is shown below. Which statement about the function is true? The function is increasing for all real values of x where x < –4. The function is increasing for all real values of x where –6 < x < –2. The function is decreasing for all real values of x where x < –6 and where x > –2. The function is decreasing for all real values of x where x < –4.

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mathmate
From the attached graph, we see that
f(x) is increassing in (- &infin; , -4), and
f(x) is decreasing in ( -4, &#8734; )
therefore
The function is increasing for all real values of x where x < –4.   TRUE 
The function is increasing for all real values of x where –6 < x < –2.   (FALSE, f(x) is positive in this range)
The function is decreasing for all real values of x where x < –6 and where x > –2.   (FALSE,  f(x) is negative in this range)
The function is decreasing for all real values of x where x < –4.  (FALSE, f(x) is decreasing ∀ x>-4
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MrRoyal

The true statement about the graph of the function f(x) = –(x + 6)(x + 2) is (a) the function is increasing for all real values of x where x < –4

How to determine the true statement?

The equation of the function is given as:

f(x) = -(x + 6)(x + 2)

From the graph of the function, we can see that the function value increases up until x = -4

Hence, the function is increasing for all real values of x where x < –4

Read more about quadratic function at:

https://brainly.com/question/23680118

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