Respuesta :

transitionstate
Equation is as follow,

                                       Mg  + 2 HCl → MgCl₂  +  H₂

According to equation 24.3 g of Mg when reacted with excess of HCl produces 22.4 L (1 mole) of H₂ gas, this statement can be written as,

                          24.3 g of Mg   =   22.4 L of H₂
So,
If 24.3 g of Mg is reacted then X L of H₂ will produce,
Again
                         24.3 g of Mg   =   X L of H₂

Solving for X,

                             X   =  (24.3 g ×22.4 L) ÷ 24.3 g

                             X   =  22.4 L of H₂

Interesting! It means we are provided with exactly one mole of Mg, so obviously one mole of H₂ gas is produced which occupies 22.4 L of volume.
Eduard22sly

The volume (in litres) of H₂ that would be produced from the reaction is 22.4 L

How to determine the mole of Mg

  • Molar mass of Mg = 24.3 g/mol
  • Mass of Mg = 24.3 g
  • Mole of Mg =?

Mole = mass / molar mass

Mole of Mg = 24.3 / 24. 3

Mole of Mg = 1 mole

How to determine the mole of H₂

Mg + 2HCl → MgCl₂ + H₂

From the balanced equation above,

1 mole of Mg reacted to produce 1 mole of H₂.

Thus,

1 mole of H₂ was obtained from the reaction

How to determine the volume of H₂

1 mole of H₂ = 22.4 L

Since we obtained 1 mole of H₂, we can conclude that the volume of H₂ produced from the reaction is 22.4 L

Learn more about stoichiometry:

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