Respuesta :

Answer: Option 'b' is correct.

Step-by-step explanation:

Since we know that

Surface area of cube = 6a²

Volume of cube = a³

So, it does not include pi at all.

Surface area of pyramid is given by

[tex]\frac{1}{3}[/tex]perimeter of base × height

Volume of pyramid is given by

[tex]\frac{1}{3}[/tex]× area of base × height

And we know that base can be of 2D shapes which do not include pi at all.

Surface of tetrahedron is given by

[tex]\sqrt{3}a^2[/tex]

Volume of tetrahedron is given by

[tex]\frac{\sqrt{2}}{12}a^3[/tex]

So, it does not include pi.

Surface area of cylinder is given by

[tex]2\pi rh[/tex]

Volume of cylinder is given by

[tex]\pi r^2h[/tex]

Hence, only cylinder include pi.

Therefore, Option 'b' is correct.

boffeemadrid

Answer:

(B) cylinder

Step-by-step explanation:

Since, we know that

(A)Surface area of cube is given as:

[tex]SA=6a^2[/tex] and

Volume of cube is given as:

[tex]V=a^3[/tex]

Thus, both figures does not includes pi. Hence, this option is incorrect.

(B) Surface area of cylinder is given by:

[tex]SA=2{\pi}rh[/tex] and

Volume of cylinder is given as:

[tex]V={\pi}r^2h[/tex]

which includes pi, thus this option is correct.

(C) Surface area of pyramid is given as:

[tex]SA=\frac{1}{3}Perimeter of base{\times}height[/tex] and

Volume of pyramid is given as:

[tex]V=\frac{1}{3}area of base{\times}height[/tex]

And we know that base can be of 2D shapes which do not include pi at all.

Thus, this option is incorrect.

(D) Surface of tetrahedron is given as:

[tex]SA=\sqrt{3}a^2[/tex] and

Volume of tetrahedron is given as:

[tex]V=\frac{\sqrt{2}}{12}a^3[/tex]

which does not include pi. Hence, this option is incorrect.