The volume occupied by 0.118mol of He gas at a pressure of 1.05 atm and temperature of 322k is calculated by use of ideal gas equation
that is PV = nRT
P(Pressure)1.05 atm
v(volume)=?
n (number of moles)=0.118 mol
T(temperature)= 322K
from equation above volume(v)= nRT/p
volume(v) = (0.118 mol x 0.0821 L.atm/k.mol x322k) / 1.05 atm = 2.97 L
