Answer:
It is given that In Δ ABC
[tex]sin A=\frac{1}{4},cos A=\frac{\sqrt{15}}{4}, tan A=\frac{1}{\sqrt{15}}[/tex]
Length of perpendicular = 1=AB
length of Hypotenuse =4=AC
Length of Base = √15=BC
In ΔYZX
Length of perpendicular =6 =YZ
length of Hypotenuse =24=ZX
Length of Base = 6√15=XY
ΔYZX is similar to ΔABC, because when triangles are similar their sides are proportional.
[tex]\frac{AB}{YZ}=\frac{BC}{XZ}=\frac{AC}{XY}=\frac{1}{6}[/tex]
