Given that there are three different games played.
Game 1: Toss a coin
Game 2: Drawing a letter at random from the alphabet
Game 3: Toss two coins
From first game we need to get "tail"
we know that there are two possible cases when tossing any coin {Head , Tail}
So probability of getting tail = 1/2
From second game we need to get letter "T"
we know that there are total 26 alphabets
So probability of getting letter T = 1/26
From third game we need to get two "tail"
Possible cases are {HH, HT, TH, TT} which are 4
H means Head T means tail. We see that double tail occurs only once from 4 possible cases
So probability of getting two tail = 1/4
Now we can combine all the results to find the probability of getting a tail, the letter T, and then two tails
[tex] Probability = \frac{1}{2}\cdot\frac{1}{26}\cdot\frac{1}{4} = \frac{1}{208} [/tex]
Hence final answer will be [tex] \frac{1}{208} [/tex]
