Respuesta :

patbergj
This is what I think:
The first one, you take (x,y) both times 3
A(1,1) to A(3,3)
B(-1,1) to B(-3,3)
C(1,-1) to C(3,-3)
D(-1,-1) to D(-3,-3)

The second one, you take (x,y) both times 2
A(4,1) to A(8,2)
B(4,3) to B(8,6)
C(1,2) to C(2,4)

That is how I think you do it. I hope that I helped you.
Leader
17)
Find the length of the side of the smaller square. So subtract the x-values from each other.
1-(-1)=2
The length of the square is 2.

Now find the length of the bigger square.
3-(-3)=6     (You can also just count the units between the two points.)

Now divide the length of the bigger triangle by the length of the smaller triangle to find the scale factor used to dilate the object.

[tex]\frac{6}{2}={\boxed{3}[/tex]

The scale factor is 3.

18)
Find the base of the larger triangle.
The y-value for point B is 6 and the y-value for point A is 2. Just subtract to find the length of BA.
6-2=4

Now find the base of the smaller triangle.
The y-value for point B is 3 and the y-value for point A is 1. Just subtract to find the length of B'A'.
3-1=2

Divide the base of the smaller triangle by that of the larger triangle.

[tex]\frac{2}{4}={\boxed{\frac{1}{2}}[/tex]

The scale factor is 1/2.
_____________________________________________________

Now you might be wondering why I divided the smaller triangle by the larger one but I didn't follow the same procedure for the squares. If you look closely, the smaller triangle is the new figure after the scale factor dilation while the larger square is the new figure after the scale factor dilation. Just look at the coordinates. The coordinates for a changed figure always has an apostrophe at the end of it. The bigger square in question 17 has the apostrophes so I knew that the larger square was the new figure after the dilation. And the smaller triangle in question 18 has the apostrophes so I knew that the smaller triangle was the new figure after the dilation.

Otras preguntas