Respuesta :
32.6% of 1.4 Mw
= (0.326) x (1,400,000 joules/second)
= 456,400 joules/second .
1 year
= (365 da) x (86,400 sec/da) = 31,536,000 seconds
(456,000 joules/sec) x (31,536,000 sec) = 1.438 x 10¹³ Joules
(That's 1.438 x 10⁷ Megajoules, or 3,994,560 kWh)
Answer:
The energy delivered by turbine is 3.99 x 10^6 KWhr OR 14393 GJ
Explanation:
First, we need to calculate the amount of power delivered by the turbine. That is given by the formula:
Actual Power Delivered by Turbine = P = 32.6% of the Maximum Capacity
P = (0.326)(1.4 MW)
P = 0.4564 MW = 456.4 KW
Now, the time period is given as 1 year, which can be converted to hours as follows:
Time Period = t = (1 year)(365 days/year)(24 hr/day)
t = 8760 hours
Now, the energy generated by the turbine in this period is given as:
Energy = E = Pt
E = (456.4 KW)(8760 hr)
E = 3.99 x 10^6 KWhr
Converting this into Joules:
E = (3.99 x 10^6 KWhr)(3.6 x 10^6 J/1KWhr)
E = 14393 GJ