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A closely wound rectangular coil of 80 turns has dimensions 25.0 cm by 40.0 cm. the plane of the coil is rotated from a position in which it makes an angle of 37.0 degrees with a magnetic field of 1.10 t to a position perpendicular to the field. the rotation takes 0.0600 s. what is the average emf e induced in the coil

Respuesta :

jushmk
Average emf induced = -N*magnetic flux change rate

Where,
N = Number of turns = 80
Magnetic flux change rate = Change of flux / time = (BA-BA CosФ)/Time

B= 1.1 T, A = 0.25*0.40 = 0.1 m^2, Ф = 37°

Therefore,
Magnetic flux change rate  = (1.1*0.1 -1.1*0.1 Cos 37)/0.06 = 0.0222 Wb/s

Ten,
Average emf induced = -80*0.0222 = -1.772 V

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