Respuesta :
Answer:
Speed of Car A is 80 km/h and speed of Car B is 60 km/h.
Step-by-step explanation:
let v1 be speed of car A and v2 be speed of car B.
Then According to Question,
If they move in the same direction, then Car A will travel an ( x + 280 ) km while Car B will travel an x km. They both cover this in 14 hr.
using speed distance formula, we get
v1 × 14 = x + 280
v2 × 14 = x
[tex]v1=\frac{x}{14}+\frac{280}{14}=\frac{x}{14}+20[/tex]
[tex]v2=\frac{x}{14}[/tex]
v1 = v2 + 20 .................(1)
Moving towards each other, they'll collectively cover 280 km in 2 hours.
2 × (v1 + v2) = 280
2 × (v2 + 20 + v2) = 280 (from eqn (1))
v2 + v2 + 20 = 140
2 × v2 = 120
v2 = 60
v1 = 60 + 20 = 80
Therefore, Speed of Car A is 80 km/h and speed of Car B is 60 km/h.
The car going from point A is moving at 80 km/h and the car going from point B is moving at 60 km/h.
Speed
Speed is the ratio of the distance travelled to time taken. It is given by:
Speed = distance / time
Let x represent the speed of car at point A and y represent the speed of car at point B.
If the cars move to meet each other, they’ll meet in 2 hours. Hence:
x = d₁ / 2
d₁ = 2x
Also:
y = d₂ / 2
d₂ = 2y
The distance between which is 280 km. Therefore:
d₁ + d₂ = 280
2x + 2y = 280 (1)
The car going from point A will catch up with the car going from point B in 14 hours if moving in same direction. Hence:
x = d₁ / 14
d₁ = 14x
Also:
y = d₂ / 14
d₂ = 14y
d₁ = d₂ + 280
14x = 14y + 280
14x - 14y = 280 (2)
Solving the equations simultaneously gives:
x = 80, y = 60
The car going from point A is moving at 80 km/h and the car going from point B is moving at 60 km/h.
Find out more on speed at: https://brainly.com/question/4931057
