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A balloon rubbed against denim gains a charge of −8.0 µc. what is the electric force between the balloon and the denim when the two are separated by a distance of 6.0 cm? (assume that the charges are located at a point.) the value of the coulomb constant is 8.98755 × 109 n · m2 /c 2 . include direction of the force. answer in units of n.

Respuesta :

jushmk
From Coulombs law,

F= {k*Q1*Q2}/d^2

Where, F= electric force, Q1&Q2 = charges in respective surfaces, d= distnace of separation.
In the current scenario, Q1= -8 micro C, Q2 = +8 micro C, d= 6 cm = 0.06 m, k= Coulomb's constant = 8.98755*10^9 N.m^2/C^2

Therefore,
F= {8.98755*10^9*-8*8}/0.06^2 = -1.6*10^14 N

-ve sign shows that the force is towards the denim.
onyebuchinnaji

The electric force between the balloon and the denim is 159.78 N.

The given parameters:

  • Charge of the balloon, q = -8μC
  • Distance between the balloon and the denim, r = 6.0 cm

The electric force between the balloon and the denim is calculated by applying Coulomb's law for a point charge;

[tex]F = \frac{kq^2}{r^2} \\\\F = \frac{8.98755 \times 10^9 \times (8\times 10^{-6})^2}{(6\times 10^{-2})^2} \\\\F = 159.78 \ N[/tex]

Thus, the electric force between the balloon and the denim is 159.78 N.

Learn more about Coulomb's law here: https://brainly.com/question/506926

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