Total electron element having = 36
In order to find number of Protons we will subtract 2 from 36 because 2 electrons are extra with respect to protons, So number of protons are,
# of protons = 36 - 2 = 34
Means, this element has atomic number 34 and electronic configuration of this element is,
1s², 2s², 2p⁶, 3s², 3p⁶, 4s², 3d¹⁰, 4p⁴
Now, Valence Shell = 4 = Element is present in Period 4
Valence Electrons = 6 = Element is present in Group 6
Result;
This element is Selenium, with atomic number 34 and atomic mass 79 (# of protons + # of neutrons). And the correct symbol is,
⁷⁹₃₄Se⁻²
