Respuesta :
C+A=342
$5C+$12A=$2,550
5C+5A=1710
5C+12A=2550
-7C=-840
C=120
5(120)+12A=2550
600+12A=2550
12A=1950
A=163
$5C+$12A=$2,550
5C+5A=1710
5C+12A=2550
-7C=-840
C=120
5(120)+12A=2550
600+12A=2550
12A=1950
A=163
Answer: C=222 and A =120
Step-by-step explanation:
Let C be the number of children tickets and A be the number of adult tickets.
Then, According to the question, we have the following system:-
[tex]C+A=342........................(1)\\5C+12A=2550........................(2)[/tex]
Multiply equation (1) by 5 on both sides ,we get
[tex]5C+5A=1710..........(3)[/tex]
Eliminate equation (3) from equation (2), we get
[tex]7A=840\\\Rightarrow\ A=120[/tex]
Substitute the value of A in (1), we get
[tex]C+120=342\\\Rightarrow\ C=222[/tex]
Hence, the number of children tickets sold = 222 and the number of adult tickets sold =120