Agent Bourne transferred classified files from the CIA mainframe into his flash drive. The drive has 36.5 megabytes on it before the transfer, and the transfer happened at a constant rate. After 125 seconds, there were 549 megabytes on the drive. The drive had a maximum capacity of 1000 megabytes. What was the speed of the transfer?

The speed was 4.1 MB/sec.

We first find the amount that was transferred within the first 125 seconds:

549-36.5=512.5

Now we divide this by 125, the number of seconds:
512.5/125 = 4.1

Answer Link

eudora eudora · Answer 2 · 2019-06-06T21:29:41+02:00

Answer:

speed of transfer = 4.10 megabyte per second

Step-by-step explanation:

The drive was already having 36.5 megabytes on it before the transfer.

After transferring data there were 549 megabytes on the flash drive.

So data transferred = 549 - 36.5 = 512.50 megabytes

Time taken to transfer this data = 125 seconds

Then speed of transfer = [tex]\frac{\text{Megabytes available on flash drive}}{Time taken to transfer }[/tex]

= [tex]\frac{512.50}{125}=4.10[/tex] megabytes per second

Therefore, answer will be speed of transfer = 4.10 megabyte per second