Respuesta :
Charles law states that volume of gas is directly proportional to temperature of gas at constant pressure and fixed amount of gas.
V / T = k
where V - volume , T - temperature in Kelvin and k - constant
[tex] \frac{V1}{T1} = \frac{V2}{T2} [/tex]
where parameters for the first instance are on the left side and parameters for the second instance are on the right side of the equation
T1 = 25 °C + 273 = 298 K
T2 = 35 °C + 273 = 308 K
substituting values in the equation,
[tex] \frac{5.00L}{298 K} = \frac{V}{308 K} [/tex]
V = 5.17 L
new volume is 5.17 L
V / T = k
where V - volume , T - temperature in Kelvin and k - constant
[tex] \frac{V1}{T1} = \frac{V2}{T2} [/tex]
where parameters for the first instance are on the left side and parameters for the second instance are on the right side of the equation
T1 = 25 °C + 273 = 298 K
T2 = 35 °C + 273 = 308 K
substituting values in the equation,
[tex] \frac{5.00L}{298 K} = \frac{V}{308 K} [/tex]
V = 5.17 L
new volume is 5.17 L
The ideal gas equation gives the relation between the volume, pressure, temperature, and moles of the gas. The new volume of the gas will be 5.17 L.
What is Charle's law?
Charle's law gave the direct relationship between the volume of the gas and its temperature. The law is given as:
[tex]\rm \dfrac{V}{T} = k[/tex]
or
[tex]\rm \dfrac{V_{1}}{T_{1}} = \rm \dfrac{V_{2}}{T_{2}}[/tex]
Given,
Initial volume = 5.00 L
Initial temperature = 298 K
Final temnperature = 308K
Substituting values in the equation:
[tex]\begin{aligned} \rm \dfrac{5}{298} &= \rm \dfrac{V_{2}}{308}\\\\&= \dfrac{5\times 308}{298}\\\\&= 5.17 \;\rm L\end{aligned}[/tex]
Therefore, 5.17 L is the final volume of the gas sample.
Learn more about Charle's law here:
https://brainly.com/question/14562209
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