For this case we have the following equation:
Q = Av
Where the area is given by:
A = pi * r ^ 2
A = pi * (d / 2) ^ 2
A = (pi / 4) * d ^ 2
Substituting we have:
Q = ((pi / 4) * d ^ 2) v
From here, we clear the diameter:
d = root ((4 / pi) * (Q / v))
Substituting values we have:
d = root ((4 / pi) * (50/600))
d = 0.36 feet
Answer:
The diameter of a pipe that allows a maximum flow of 50ft ^ 3 / min of water flowing at a velocity of 600ft / min is:
d = 0.36 feet
