Respuesta :
The probability is 3/6 (1/2) as there are 3 prime numbers on a dice (2,3,5) and also 3 odd numbers on a dice (1,3,5)
Christina rolls a number cube twice.
Number of outcomes in a cube = 1,2,3,4,5,6 = 6 outcomes
Prime numbers = 2,3,5 = 3 outcomes
Odd numbers = 1,3,5 = 3 outcomes
probability that she rolls a prime number = [tex] \frac{outcome of a prime number }{total number of outcomes} [/tex] =[tex] \frac{3}{6} = \frac{1}{2} [/tex]
probability that she rolls a odd number = [tex] \frac{outcome of a odd number }{total number of outcomes} [/tex] =[tex] \frac{3}{6} = \frac{1}{2} [/tex]
probability (a prime number and then an odd number) =
[tex] \frac{1}{2} [/tex] * [tex] \frac{1}{2} [/tex] = [tex] \frac{1}{4} [/tex]
