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The ages of two groups of karate students are shown in the following dot plots: A dot plot shows Age in years on the horizontal axis. For Group A, there are 2 dots on 4, 5 dots on 5, 3 dots on 7, 4 dots on 8, 2 dots on 9, 2 dots on 11, and 1 dot on 14. For Group B, there is 1 dot on 7, 2 dots on 8, 1 dot on 9, 1 dot on 11, 1 dot on 16, 2 dots on 19, 2 dots on 20, 2 dots on 21, and 1 dot on 26.

The mean absolute deviation (MAD) for group A is 2.07 and the MAD for group B is 5.51. Which of the following observations can be made using these data?

Respuesta :

singingpenguin
Group A:1 dot at 9:     1 x    9 =     97 dots at 10: 7 x 10 =   708 dots at 15: 8 x 15 = 1208 dots at 17: 8 x 17 = 1366 dots at 19: 6 x 19 = 114
Mean: (9+70+120+136+114) / (1+7+8+8+6) = 449/30 = 14.97
Group B:6 dots at 10: 6 x 10 = 605 dots at 14: 5 x 14 = 706 dots at 18: 6 x 18 = 1085 dots at 25: 5 x 25 = 1254 dots at 28: 4 x 28 = 1124 dots at 29: 4 x 29 = 116
mean: (60+70+108+125+112+116) / (6+5+6+5+4+4) = 591 / 30 = 19.70
The group that has a lower mean age of painting students is Group A. Its mean is 14.97 or 15 years of age.
okpalawalter8

The observation made using the data is that Group A has the youngest average age of painting students.

Which of the following observations can be made using the data?

Generally, the equation for the  mean is mathematically given as

For Group A

x=sum of dots/ number of dots

Therefore

X= (9+70+120+136+114) / (1+7+8+8+6)

X= 449/30

X= 14.97

For Group B

X'= (60+70+108+125+112+116) / (6+5+6+5+4+4)

X' = 591 / 30

X' = 19.70

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